A^2-(8/3)a=8

Solution for A^2-(8/3)a=8 equation:

^2-(8/3)A=8

We move all terms to the left:

^2-(8/3)A-(8)=0


Domain of the equation: 3)A!=0

A!=0/1

A!=0

A∈R


determiningTheFunctionDomain
-(8/3)A-8+^2=0

We add all the numbers together, and all the variables

-(+8/3)A-8+^2=0

We add all the numbers together, and all the variables

-(+8/3)A=0

We multiply parentheses

-8A^2=0

a = -8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-8)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$A=\frac{-b}{2a}=\frac{0}{-16}=0$